A chemistry student must write down in her lab notebook the concentration of a solution of sodium hydroxide. The concentration of a solution equals the mass of what's dissolved divided by the total volume of the solution.

Here's how the student prepared the solution:

She put some solid sodium hydroxide into the graduated cylinder and weighed it. With the sodium hydroxide added, the cylinder weighed. She added water to the graduated cylinder and dissolved the sodium hydroxide completely. Then she read the total volume of the solution from the markings on the graduated cylinder. The total volume of the solution was.

What concentration should the student write down in her lab notebook?

Question

Logan Padilla

Chemistry

28 July, 09:57

A chemistry student must write down in her lab notebook the concentration of a solution of sodium hydroxide. The concentration of a solution equals the mass of what's dissolved divided by the total volume of the solution.

Here's how the student prepared the solution:

She put some solid sodium hydroxide into the graduated cylinder and weighed it. With the sodium hydroxide added, the cylinder weighed. She added water to the graduated cylinder and dissolved the sodium hydroxide completely. Then she read the total volume of the solution from the markings on the graduated cylinder. The total volume of the solution was.

What concentration should the student write down in her lab notebook?

+3

Answers (1)

Know the Answer?

Addison Juarez · Answer 1

The concentration the student should write down in her lab is 2.2 mol/L

Explanation:

Atomic mass of the elements are:

Na: 22.989 u

S: 32.065 u

O: 15.999 u

Molar mass of sodium thiosulfate, Na2S2O3 = (2*22.989 + 2*32.065 + 3*15.999) g/mol = 158.105 g/mol.

Mass of Na2S2O3 taken = (19.440 - 2.2) g = 17.240 g.

For mole (s) of Na2S2O3 = (mass taken) / (molar mass)

= (17.240 g) / (158.105 g/mol) = 0.1090 mole.

Volume of the solution = 50.29 mL = (50.29 mL) * (1 L) / (1000 mL)

= 0.05029 L.

To find the molar concentration of the sodium thiosulfate solution prepared we use the formula:

= (moles of sodium thiosulfate) / (volume of solution in L)

= (0.1090 mole) / (0.05029 L)

= 2.1674 mol/L