A 20 g piece of metal with specific heat 0.4 J/g.°C absorbs 3.9 kilojoules of heat,

calculate the change in temperature. Formula: Q = mcAT

given that

... the mass of the metal is 20g (0.02kg)

... specific heat capacity (c) is 0.4J/g°C

... ΔT=?

heat (Q) = 3.9KJ (3900J)

Q=mcΔT

ΔT = Q/mc

... = 3900: (20g x 0.4J/g°C)

... = 487.5°C