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22 August, 21:55

Determine what mass of sodium nitrite, NaNO2, would be required to prepare a buffer, Buffer A, with a pH of 3.13 from 50.0 mL of 1.0 M nitrous acid, NaNO2. The Ka and pKa for nitrous acid is 4.0 x 10-4 and 3.40 respectively.

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  1. 22 August, 22:18
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    1.85 g

    Explanation:

    The strategy here is to utilize the Henderson-Hasselbach equation

    pH = pKa + log [A⁻] / [HA]

    to calculate the ratio log [A⁻] / [HA], and from there to calculate the concentration [A⁻] and finally the mass of NaNO₂ from the number of moles assuming the final buffer volume is 50.0 mL (that is the volume does not change by the addition of NaNO₂)

    pH = pKa + log [NO₂⁻]/[HNO₂]

    3.13 = 3.40 + log [NO₂⁻]/[HNO₂]

    - 0.27 = log [NO₂⁻]/[HNO₂]

    taking the inverse log function to both sides of this equation

    0.54 = [NO₂⁻]/[HNO₂]

    Now [HNO₂] = 1.0 M, therefore [NO₂⁻] = [NaNO₂] =

    0.54 x 1.0 M = 0.54 M

    from M = mol / L we get

    mol = 0.54 mol/L x 0.050L = 0.027 mol

    the molar mass of NaNO₂ is = 68.99 g / mol, so the mass of 0.027 mol is

    0.027 mol x 68.99 g/mol = 1.85 g
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