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18 October, 22:59

For the following reaction, 2 SO2 (g) + O: (g) 2 SO, (g) the equilibrium constant, K, is 1.32 at 627°C. What is the equilibrium constant for the reaction below? SO; (g) + 1/2 O: (g) SO, (g)

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  1. 18 October, 23:18
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    1.15

    Explanation:

    2SO₂ + O₂ ⟶ 2SO₃; K = 1.32

    SO₂ + ½O₂ ⟶ SO₃; K₁ = ?

    When you divide an equation by 2, you take the square root of its equilibrium constant.

    K₁ = √1.32 = 1.15

    The equilibrium constant is 1.15.
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