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9 July, 22:39

Two hundred grams of a substance requires 9.76 kj of heat to raise its temperature from 25degrees C to 45 degrees C

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  1. 9 July, 22:52
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    Given:

    9.76 kj of heat

    from 25degrees C to 45 degrees C

    200 grams of substance

    Required:

    Cp in kJ/kg-K

    Solution:

    H = mCpT

    (9.76 kJ) = (200g) (1kg/1000g) Cp (45 - 25) K

    Cp = 2.44 kJ/kg-K
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