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28 November, 15:17

Calculate the heat of decomposition for this process at constant pressure and 25°C: CaCO3 (s) → CaO (s) + CO2 (g) The standard enthalpies of formation for the reactant are: ΔHf CaCO3 (s) = - 1206.9 kJ/mol; ΔHf CaO (s) = - 635.6 kJ/mol; ΔHf CO2 (g) - 393.5 kJ/mol

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  1. 28 November, 15:37
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    177.8kJ/mol

    Explanation:

    In this reaction, the heat of decomposition is the same as the heat of formation. This is a decomposition reaction.

    Given parameters:

    ΔHf CaCO₃ = - 1206.9kJ/mol

    ΔHf CaO = - 635.6 kJ/mol

    ΔHf CO₂ = - 393.5 kJ/mol

    The heat of decomposition =

    Sum of ΔHf of products - Sum of ΔHf of reactants

    The equation of the reaction is shown below:

    CaCO₃ → CaO + CO₂

    The heat of decomposition = [ - 635.6 + (-393.5) ] - [-1206.9 ]

    = - 1029.1 + 1206.9

    = 177.8kJ/mol
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