Ask Question
17 March, 02:43

Pon heating, a 5.41 g sample of a compound decomposes into 2.37 g n 22 and 3.04 g h 22 o. if the molar mass of the compound is 64.06 g/mol, what is the chemical formula of the compound

+3
Answers (1)
  1. 17 March, 03:10
    0
    Initially note that 2.37 g + 3.04 g = 5.41 g, which means that the sample was a compound of only N, H and O.

    Convert the masses of N2 and H2O into number of moles by using the molar masses of each.

    1) N

    moles = mass of N2 / molar mass of N2 = 2.37 g / (14.0 g/mol) = 0.169 mol of N

    2) H2O

    moles = mass of H2) / molar mass of H2O = 3.04 g / (18.0 g / mol) = 0.169 mol

    0.169 moles of H2O = > 2 * 0.169 moles of H and 0.169 moles of O

    3) Emipirical formula

    N: 0.169 / 0.169 = 1

    H: 2 * 0.169 / 0.169 = 2

    O: 0.169 / 0.169 = 1

    => NH2O

    4) Molar mass of the empirical formula: 14.0 g/mol + 18 g/mol = 32 g/mol

    5) Number of times that the empirical formula is contained in the molecular formula: 64 g/mol / 32 g / mol = 2

    6) Molecular formula = 2 * Empirical formula = N2H4O2

    Answer: N2H4O2
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Pon heating, a 5.41 g sample of a compound decomposes into 2.37 g n 22 and 3.04 g h 22 o. if the molar mass of the compound is 64.06 g/mol, ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers