If the concentration of an analyte in a solution prepared by digesting a 2.05 g solid sample and making up to 100 mL, is found to be 21.1 mg L-1. What was the mass percentage of the analyte in the original sample?

Question

Jamison Daniel

Chemistry

10 November, 21:51

If the concentration of an analyte in a solution prepared by digesting a 2.05 g solid sample and making up to 100 mL, is found to be 21.1 mg L-1. What was the mass percentage of the analyte in the original sample?

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Answers (1)

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Alyson · Answer 1

Mass percentage of analyte = 0.10%

Explanation:

The mass of analyte in the solution is calculated as follows:

n = CV = (21.1 mgL⁻¹) (100 mL) (1L/1000mL) = 2.11 mg

The mass percentage of the analyte is calculated as follows:

(g analyte) / (g sample) x 100%

(2.11 mg) (1g/1000g) / (2.05g) x 100% = 0.10%