A solution of CaCl₂CaCl₂ in water forms a mixture that is 31.0%31.0% calcium chloride by mass. If the total mass of the mixture is 650.5 g, 650.5 g, what masses of CaCl₂CaCl₂ and water were used?

Question

Jocelynn Carpenter

Chemistry

27 July, 16:05

A solution of CaCl₂CaCl₂ in water forms a mixture that is 31.0%31.0% calcium chloride by mass. If the total mass of the mixture is 650.5 g, 650.5 g, what masses of CaCl₂CaCl₂ and water were used?

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There is used 201,655 grams CaCl2 and 448,845 grams of water (H2O)

Explanation:

w% = m (CaCl2) / m (total) x 100%

-> (m (Cacl2) = m (total) x w%) / 100 %

-> m (CaCl2) = (650,5g x 31%) / 100% = 201,655g

Total mass : m (total) = m (CaCl2) + m (H2O)

-> m (H2O) = m (total) - m (CaCl2)

->m (H2O) = 650,5g - 201,655g = 448,845g