An investor paid market price for a chunk of gold that he was told was pure. The gold bar had a mass of 440 g, but was slightly irregular so an exact volume could not be calculated. The investor filled a large graduated cylinder with water, immersed the chunk of gold, and observed an increase in the apparent volume of material in the graduated cylinder of 25.0 ml. Pure gold has a density of 19.3 g/cm 3. Did the investor get his money's worth? Why or why not?

Question

Drake Gonzalez

Chemistry

27 July, 15:31

An investor paid market price for a chunk of gold that he was told was pure. The gold bar had a mass of 440 g, but was slightly irregular so an exact volume could not be calculated. The investor filled a large graduated cylinder with water, immersed the chunk of gold, and observed an increase in the apparent volume of material in the graduated cylinder of 25.0 ml. Pure gold has a density of 19.3 g/cm 3. Did the investor get his money's worth? Why or why not?

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Answers (1)

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Marin Travis · Answer 1

No. the investor didn't get his money worth gold.

Explanation:

Density of pure gold = 19.3 g/cm³

Mass of gold bar = 440 g

volume replaced by gold bar = 25 ml

Now we have to find the volume of the gold bar using its mass and volume as,

Volume = Mass / density = 440 g / 19.3 g/cm³

= 22.79 ≈ 23 ml

So the investor didn't get his money worth gold.