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25 May, 08:57

The maximum allowable concentration of pb2 + ions in drinking water is 0.05 ppm (i. e., 0.05 g of pb2 + in 1 million grams of water). (a) what is the pb2 + concentration of an underground water supply at equilibrium with the mineral anglesite (pbso4) (ksp = 1.6 * 10-8) ?

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  1. 25 May, 09:24
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    PbSO₄ partially dissociates in water. the balanced equation is;

    PbSO₄ (s) ⇄ Pb²⁺ (aq) + SO₄²⁻ (aq)

    Initial - -

    Change - X + X + X

    Equilibrium X X

    Ksp = [Pb²⁺ (aq) ] [SO₄²⁻ (aq) ]

    1.6 x 10⁻⁸ = X * X

    1.6 x 10⁻⁸ = X²

    X = 1.3 x 10⁻⁴ M

    Hence the Pb²⁺ concentration in underground water is 1.3 x 10⁻⁴ M.

    [Pb²⁺] = 1.3 x 10⁻⁴ M.

    = 1.3 x 10⁻⁴ mol / L x 207 g / mol

    = 26.91 ppm
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