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21 February, 18:47

Consider the mechanism. Step 1: 2 A ⟶ B + C slow Step 2: B + C ⟶ E fast Overall: 2 A ⟶ E Determine the rate law for the overall reaction, where the overall rate constant is represented as k.

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  1. 21 February, 19:12
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    rate = k[A]²

    Explanation:

    Two principles:

    The steps in a mechanism are elementary reactions, so the exponents in the rate laws are the coefficients in the steps. No reaction can go faster than its slowest step.

    Step 1: 2A ⟶ B + C (slow)

    Step 2: B + C ⟶ E (fast)

    Overall: 2A ⟶ E

    The rate law for the reaction is the same as that for Step 1:

    rate = k[A]²
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