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23 January, 07:39

Calcium reacts with sulfur forming calcium sulfide. what is the theoretical yield (g) of cas (s) that could be prepared from 1.6 g of ca (s) and 4.25 g of sulfur (s) ? enter your answer with two decimal places. do not type units with your answer.

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  1. 23 January, 07:52
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    The balanced equation for the above reaction is;

    Ca + S - - - > CaS

    stoichiometry of Ca to S is 1:1

    Number of Ca moles - 1.6 g / 40 g/mol = 0.04 mol

    Number of S moles - 4.25 g / 32 g/mol = 0.13 mol

    since Ca to S molar ratio is 1:1, there's excess amount of S present.

    Ca is the limiting reactant.

    stoichiometry of Ca to CaS is 1:1

    Number of CaS moles to be formed - 0.04 mol

    Therefore mass of CaS - 0.04 mol x 72 g/mol = 2.88 g

    therefore theoretical yield is 2.88
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