Given the reaction: 6 NaOH + 2 Al - --> 2 Na3AlO3 + 3 H2 How many moles of NaOH are required to produce 3.5 moles of hydrogen?

7 moles

Explanation:

The balanced equation for the reaction is given below:

6NaOH + 2Al - > 2Na3AlO3 + 3H2

The number of moles of NaOH required to produce 3.5 moles of hydrogen, H2 can be obtaine as follow:

From the balanced equation above, 6 moles of NaOH reacted to produce 3 moles of H2.

Therefore, Xmol of NaOH will react to produce 3.5 moles of NaOH.

Xmol of NaOH = (6 x 3.5) / 3

Xmol of NaOH = 7 moles

Therefore, 7 moles of NaOH are required.