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1 December, 14:01

A 45.30 g sample of solid mercury is initially at - 59.00°C. If the sample is heated at constant pressure ( = 1 atm), kJ of heat are needed to raise the temperature of the sample to 30.00°C.

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  1. 1 December, 14:31
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    0.165kJ

    Explanation:

    Formula to use for such a question is;

    Energy = number of mole x molar gas constant x change in temperature

    Number of mole = reacting mass of mercury / molar mass of mercury = 45.30/200.58 = 0.226moles

    Change in temperature = final temperature - initial temperature = 30 - (-59) = 30 + 59 = 89 Kelvin

    E = nRT = 0.226 x 8.314 x 89

    Energy = 165.35Joules

    Energy in kJ = 165.35/1000 = 0.165kJ
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