How many liters of methane gas (CH4) need to be combusted to produce 8.5 liters of water vapor, if all measurements are taken at the same temperature and pressure? Show all of the work used to solve this problem. CH4 (g) + 2O2 (g) yields CO2 (g) + 2H2O (g)

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27 November, 02:38

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Malia Sanders · Answer 1

8.5L H2O (1 mol H2O/22.4L) =.37946 mol H2O

.3796 mol H2O (1 mol CH4/2 mol H2O) =.18973 mol CH4

.18973 mol CH4 (22.4L/1mol CH4) = 4.25L CH4 gas