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1 December, 16:23

Gaseous neon has a density of 0.900 g/L at standard conditions. How many neon atoms are in 1.00 L of neon gas at standard conditions?

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  1. 1 December, 16:43
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    Answer: 1.348 * 10^23 atoms

    Explanation:

    Given that volume = 1.00L

    At standard condition, the volume of a gas is 22.4L/mol (at S. T. P)

    Volume = mole / volume at STP

    1 = mole/22.4

    Mole = 22.4mol.

    Also

    Mole = number of atoms / Avogradro constant

    Where avogrado's constant = 6.02*10²³

    22.4 = number of atoms/6.02*10²³

    Number of atoms = 1.348*10^25atoms
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