The molar solubility of ba3 (po4) 2 is 8.89 x 10-9 m in pure water. calculate the ksp for ba3 (po4) 2. the molar solubility of ba3 (po4) 2 is 8.89 x 10-9 m in pure water. calculate the ksp for ba3 (po4) 2. 5.55 x 10-41 5.33 x 10-37 8.16 x 10-31 6.00 x 10-39 4.94 x 10-49

Question

Hamza Perez

Chemistry

29 October, 16:19

The molar solubility of ba3 (po4) 2 is 8.89 x 10-9 m in pure water. calculate the ksp for ba3 (po4) 2. the molar solubility of ba3 (po4) 2 is 8.89 x 10-9 m in pure water. calculate the ksp for ba3 (po4) 2. 5.55 x 10-41 5.33 x 10-37 8.16 x 10-31 6.00 x 10-39 4.94 x 10-49

+3

Answers (1)

Know the Answer?

Dax Campbell · Answer 1

Answer is: The molar solubility of ba3 (po4) 2 is 6.00 x 10-39.

Balanced chemical reaction: Ba₃ (PO₄) ₂ (s) → 3Ba²⁺ (aq) + 2PO₄³⁻ (aq).

s (Ba₃ (PO₄) ₂) = 8.89·10⁻⁹ M.

[Ba²⁺] = 3s (Ba₃ (PO₄) ₂) = 3s.

[PO₄³⁻] = 2s.

Ksp = [Ba²⁺]³ · [PO₄³⁻]².

Ksp = (3s) ³ · (2s) ².

Ksp = 108s⁵.

Ksp = 108· (8.89·10⁻⁹ M) ⁵.

Ksp = 108 · 5.55·10⁻⁴¹ = 6·10⁻³⁹.