An air mattress is filled with 0.55 moles of air. The air inside the mattress has a temperature of 295 K and a gauge pressure of 3.5 kilopascals. What is the volume of the air mattress?

Answer: 385.4132857

Explanation:

Using the equation, PV=nRT, you can solve this problem.

P = 3.5 kPa V=? n = 0.55 moles of air T = 295K R = 8.314 (L kPa/mol K)

We use the constant rate of 8.314 because we are using kilopascals in this problem.

Using simple algebra we get-

V = (0.55 moles) (8.314 L kPa/mol k) (295 K) / 3.5 kPa

Using the calculator, we would get the answer of 385.4132857 L.

And whatever the significant figure is asked for, for example, 3 significant figures: the answer would be 385 liters.