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13 June, 09:43

A 7.5 L cylinder contains 5 moles of gas at a temperature of 274°C. What is its pressure in kiloPascals (kPa) ?

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  1. 13 June, 09:54
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    Answer;

    = 3032.15 kPa

    Explanation;

    Using the equation;

    PV = nRT, where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol-1.

    Volume = 7.5 L, T = 274 + 273 = 547 K, N = 5 moles

    Therefore;

    Pressure = nRT/V

    = (5 * 0.08206 * 547) / 7.5 L

    = 29.925 atm

    But; 1 atm = 101325 pascals

    Hence; Pressure = 3032150.63 pascals

    = 3032.15 kPa
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