What is the pH of the solution obtained by mixing 30 mL of. 25 M HCL in 30 mL of. 125 M NaOH

pH after mixing = 1.2

Explanation:

HCl + NaOH = > NaCl + H₂O

Will show only the reactants for the solution set ...

Given 30ml (0.25M HCl) + 30ml (0.125M NaOH)

=> 0.030 (0.25) mole HCl + 0.030 (0.125) mole NaOH

=> 0.0075mole HCl + 0.00345mol NaOH

moles HCl neutralized = moles NaOH added into solution (1:1 reaction ratio)

=> (0.0075 - 0.00375) mol HCl remains in excess in 60ml of solution

=> (0.00375mol/0.060L) HCl = 0.0625M in HCl

pH = - log[HCl] = - log[H⁺] = - log (0.0625) = - (-1.2) = 1.2