Calculate the pH of a solution that has a [OH-] of 2.6 * 10^-6 M.

A. 8.4

B. 6.5

C. 7.7

D. 6.29

A. 8.4

Explanation:

[OH⁻] = 2.6 * 10⁻⁶ Take the negative log of each side

-log[OH⁻] = pOH = 5.59 Apply the pH/pOH relation

pH + pOH = 14.00 Insert the value of pOH

pH + 5.59 = 14.00 Subtract 5.59 from each side

pH = 14.00 - 5.59 = 8.41