If i have 6 grams of sugar and dissolve it in 74 mL of water, what is the concentration?

Given that

Amount of sugar = 6 g

Volume of water = 74 ml or 0.074 L

Number of moles of sugar = amount in g / molar mass

= 6 g / 342.3 g/mol

=0.018 moles

Therefore molarity or concentration = 0.018 mole / 0.074 L

= 0.24 M