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9 May, 03:49

The interior of a refrigerator has a volume of 0.600 m3. the temperature inside the refrigerator in 282 k, and the pressure is 101 kpa. if the molecular weight of air is 29 g/mol, what is the mass of air inside the refrigerator? the ideal gas constant is r = 8.314 j/mol ∙ k = 0.0821 l ∙ atm/mol ∙ k.

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  1. 9 May, 03:58
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    In this instance we can use the ideal gas law equation to find the number of moles of gas inside the refrigerator

    PV = nRT

    where

    P - pressure - 101 000 Pa

    V - volume - 0.600 m³

    n - number of moles

    R - universal gas constant - 8.314 J/mol. K

    T - temperature - 282 K

    substituting these values in the equation

    101 000 Pa x 0.600 m³ = n x 8.314 J/mol. K x 282 K

    n = 25.8 mol

    there are 25.8 mol of the gas

    to find the mass of gas

    mass of gas = number of moles x molar mass of gas

    mass = 25.8 mol x 29 g/mol = 748.2 g

    mass of gas present is 748.2 g
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