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11 August, 19:37

If I have 72 liters of argon gas held at a pressure of 3.4 atm and a temperature of 225k how many grams of argon do I have

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  1. 11 August, 20:04
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    516.77 grams of Argon gas is present

    Explanation:

    Using the gas formula

    PV = nRT

    number of moles (n) = mass / molar weight or mass

    P = pressure = 3.4 atm

    V = volume = 72 L

    R = gas constant = 0.082 L atm mol^-1 K^-1

    T = temperature = 225 K

    MM = molar mass of Ar = 38.984 g/mol

    PV = mRT / MM

    m = PV MM / RT

    m = 3.4 * 72 * 38.948 / 0.082 * 225

    m = 9534.4704 / 18.45

    m = 516.77 grams

    the mass of Ar gas you have is 516.77 grams.
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