Ask Question
8 March, 18:05

Consider the following reversible reaction l. 2H2Og 2H2g+O2g what is the equilibrium constant expression for the given system?

+2
Answers (1)
  1. 8 March, 18:07
    0
    The equilibrium consntant expression is:

    Keq = (02) x (H2) ^2 / (H20) ^2

    Explanation:

    The equilibrium constant is calculated as the ratio between products and reagents raised to their stoichiometric coefficients. In this case, Water (H20) is a reagent and the respective products are Hydrogen (H2) and Oxygen (02)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Consider the following reversible reaction l. 2H2Og 2H2g+O2g what is the equilibrium constant expression for the given system? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers