Ask Question
1 February, 17:03

What volume would 4.3 moles of hydrogen gas occupy at 45° C and 3.22 atm?

+5
Answers (2)
  1. 1 February, 17:13
    0
    34.82 L

    Explanation:

    Step 1:

    Data obtained from the question:

    Number of mole (n) = 4.3 mole

    Temperature (T) = 45°C = 45°C + 273 = 318K

    Pressure (P) = 3.22 atm

    Volume (V) = ?

    Step 2:

    Determination of the volume hydrogen gas.

    With the application of the ideal gas equation, the volume of Hydrogen gas can be obtained as follow:

    Note that the gas constant (R) = 0.082atm. L/Kmol

    PV = nRT

    3.22 x V = 4.3 x 0.082 x 318

    Divide both side by 3.22

    V = (4.3 x 0.082 x 318) / 3.22

    V = 34.82 L

    Therefore the volume occupied by the hydrogen gas is 34.82 L
  2. 1 February, 17:31
    0
    34.8 L of hydrogen gas

    Explanation:

    Now we have to use the ideal gas equation;

    PV = nRT

    P = pressure of the gas = 3.22atm

    V = volume of the gas = ?

    T = temperature of the gas = 45°C + 273 = 318K

    n = number of moles = 4.3 moles

    R = universal gas constant = 0.082atm Lmol-1K-1

    Making V the subject of the formula

    V = nRT/P

    V = 4.3*0.082*318/3.22

    V = 34.8 L
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “What volume would 4.3 moles of hydrogen gas occupy at 45° C and 3.22 atm? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers