How many liters of chlorine gas can be produced when 1.08 l of hcl react with excess o2 at stp?

Write out full equation and balance:

4HCL + O2 = 2H2O + 2Cl2

All gasses of the same mole will take up the same amount of space. No need to convert to moles.

Look at ratio of HCL to Cl2

4:2 which is 2:1 so HCl will produce half volume of Cl2

1.08 divide 2 = 0.54L