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21 December, 10:13

An unknown gas effuses at 0.770 times the effusion rate of nitrogen dioxide (NO2). Estimate the molar mass of the unknown gas. Answer in units of g/mol.

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  1. 21 December, 10:18
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    77.58g/mol

    Explanation:

    Let the rate of effusion of NO2 be R1

    The rate of effusion of the unknown gas (R2) = 0.770R1

    Molar Mass of NO2 (M1) = 14 + (2x16) = 14 + 32 = 46g/mol

    The molar mass of the unknown gas (M2) = ?

    R1/R2 = √ (M2/M1)

    R1/0.770R1 = √ (M2/46)

    1/0.770 = √ (M2/46)

    Take the square of both sides

    (1/0.770) ^2 = M2/46

    Cross multiply to express in linear form

    M2 = (1/0.770) ^2 x 46

    M2 = 77.58g/mol

    The molar mass of the unknown gas is 77.58g/mol
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