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28 July, 04:32

If 200 grams of water is to be heated from 24.0oC to 100.0oC to make a cup of tea, how much heat must be added?

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  1. 28 July, 04:35
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    According to this formula:

    Q = M*C*ΔT

    when we have M (the mass of water) = 200 g

    and C (specific heat capacity) of water = 4.18 J/gC

    ΔT (the difference in temperature) = Tf - Ti

    = 100 - 24

    = 76°C

    So by substitution:

    Q = 200 g * 4.18 J/gC * 76 °C

    = 63536 J

    ∴ the amount of heat which be added and absorbed to raise the temp from 24°C to 100°C is = 63536 J
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