When 200 grams of water cools from 50.°C to 25°C, the total amount of heat energy released by the water is?

We will use the formula q = mCΔT. where q = heat energy released. m = mass. C = specific heat of water. ΔT = change in temperature. Specific heat of water has not been given so we will just use the standard value of that which is 4.186J/g °C. q = mCΔT. q = 200 * 4.186 * (50 - 25) q = 200 * 4.186 * 25 q = 5000 * 4.186 q = 20, 930 The total amount of energy released is 20, 930 J

Heat = Mass x Specific Heat x Temperature

By putting above values we get

Heat = 20,930 Joules