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6 September, 12:51

A 6.0 M HCl solution is available. What volume is needed to make 6.00 L of 1.00 M

solution?

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  1. 6 September, 12:54
    0
    The volume of the stock solution needed is 1L

    Explanation:

    Step 1:

    Data obtained from the question. This include the following:

    Concentration of stock solution (C1) = 6M

    Volume of stock solution needed (V1) = ?

    Concentration of diluted solution (C2) = 1M

    Volume of diluted solution (V2) = 6L

    Step 2:

    Determination of the volume of the stock solution needed.

    With the dilution formula C1V1 = C2V2, the volume of the stock solution needed can be obtained as follow:

    C1V1 = C2V2

    6 x V1 = 1 x 6

    Divide both side by 6

    V1 = 6/6

    V1 = 1L

    Therefore, the volume of the stock solution needed is 1L
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