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3 November, 02:32

C2H4 (g) + H2O (g) ⇌ C2H5OH

If 14g of ethene reacts with excess steam to produce 17.25g of ethanol, what is the percentage yield of the reaction

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  1. 3 November, 02:39
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    Molecular wt if ethene = 28 g/mol

    take 14 : 28 = 0.5 mol

    since there is a 1:1 ratio between ethene and ethanol one should produce 0.5 mol

    MW ethanol = 46

    0.5 * 46 = 23 g should be produced.

    17.25/23 = 0.75 = 75% Percent yield
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