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10 July, 20:29

A 155g sample of an unknown substance was; heated from 25.0°c to 40°c. In the process, the substance absorbed 2085 J of energy. What is the specific heat of the substance?

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  1. 10 July, 20:57
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    0.897 J/g°C

    Explanation:

    Step 1:

    Data obtained from the question. This includes the following:

    Mass (M) of substance = 155g

    Initial temperature (T1) = 25.0°C

    Final temperature (T2) = 40°C

    Change is temperature (ΔT) = T2 - T1 = 40°C - 25.0°C = 15°C

    Heat Absorbed (Q) = 2085 J

    Specific heat capacity (C) of the substance = ?

    Step 2:

    Determination of the specify heat capacity of the substance.

    Applying the equation: Q = MCΔT, the specific heat capacity of the substance can be obtained as follow:

    Q = MCΔT

    C = Q/MΔT

    C = 2085 / (155 x 15)

    C = 0.897 J/g°C

    Therefore, the specific heat capacity of the substance is 0.897 J/g°C
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