Given the balanced ionic equation: 2Al (s) + 3Cu2 + (aq) → 2Al3 + (aq) + 3Cu (s) Compared to the total charge of the reactants, the total charge of the products is 1. less 2. greater 3. the same

3. - The same

Explanation:

1. - In the reactants you need to calculate the charges that you have:

2 Al (s) = zero, because the aluminum is in it based formed (that mean without charge).

3 Cu2 + = 3 x 2 + = 6 + That is the total positive charges that copper collaborate in this reaction.

2. - Then calculate the charges on the products:

2 Al3 + = 2 x 3 + = 6 + charges from the aluminum.

3 Cu (s) = zero, because the copper in this case is in the base form

3. - In this way, the charges at the begging (6+) and at the end (6+) are the same.