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4 June, 09:29

If 100.0J are added to 20g of water at 30.0c what will be the final temperature

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  1. 4 June, 09:47
    0
    31.19

    Explanation:

    H = MC x Temperature change

    100 = (20/1000) x 4200 x A

    100 = 84A

    A = 1.19

    A=X-30

    1.19=X-30

    X=30+1.19

    X=31.19
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