0.80 g of hydrogen chloride (hcl is dissolved in water to make 5.5 l of solution. what is the ph of the resulting hydrochloric acid solution?

Question

Kelton Whitehead

Chemistry

13 August, 14:21

0.80 g of hydrogen chloride (hcl is dissolved in water to make 5.5 l of solution. what is the ph of the resulting hydrochloric acid solution?

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Lillian Gallegos · Answer 1

HCl is a strong acid and so dissociates fully in water:

HCl (aq) - - > H + (aq) + Cl - (aq)

Since there is a 1:1 mole ratio between HCl and H + in this reaction, the number of moles of H + = number of moles of HCl. The number of moles of HCl can be calculated as moles = mass/RMM = 0.80g / 36.5g/mol = 0.022mol.

Since 5.5 l of solution is made, the concentration of H + is:

[H+] = 0.022mol / 5.5l = 0.004M. This can then be used to calculate pH through the equation pH = - log[H+] = - log (0.004) = 2.40