If 13.0g of CO2 gas has a volume of 0.46L at 310K, what is its pressure in millimeters of mercury?

PV = nRT - - - > p = nRT/V

n = m/M, so: p = mRT/VM, where:

p - pressure

m - mass of CO2 in grams

R - universal gas constant

T - temperature in K

V - volume in L

M - molar mass of CO2 = 44 g/mol

133.3224 Pa = 1 mm Hg

so i think You can handle this right now.