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10 December, 04:16

Find the empirical formula for a compound which contains 32.8% chromium and 67.2% chlorine

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  1. 10 December, 04:44
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    67.2% Cl = 67.2g Cl x 1 molCl / 35.45g Cl = 1.89 / 0.63 = 3 Cl

    32.8% Cr = 32.8g Cr x 1 molCr/51.99g Cr = 0.63 / 0.63 = 1 Cr

    The empirical formula is CrCl3

    First convert the mass in grams to moles, then divide both by the smallest number.
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