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10 December, 04:20

How many molecules are contained in two 540.-mg tablets of penicillin (C16H18N2O4S, molar mass 334.4 g/mol) ? Report your answer with the appropriate number of significant figures.

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  1. 10 December, 04:32
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    9.72 * 10^20 molecules

    Explanation:

    We are given;

    The mass of the compound C16H18N2O4S as 540 mg Molar mass of C16H18N2O4S = 334.4 g/mol

    We are required to determine the number of molecules in 540 mg of penicillin.

    We know that 1 mole of a compound contains molecules equivalent to the Avogadro's number. That is, 1 mole of a compound = 6.022 * 10^23 molecules Therefore, 1 mole of C16H18N2O4S = 6.022 * 10^23 molecules

    But, 1 mole = 334.4 g

    Thus, 334.4 g of C16H18N2O4S contains 6.022 * 10^23 molecules

    Mass of C16H18N2O4S = 540 mg or 0.54 g

    Molecules in 0.54 g will be;

    = (0.54 g : 334.4 g) * 6.022 * 10^23 molecules

    = 9.72 * 10^20 molecules
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