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19 May, 04:53

What mass of aluminium hydroxide is needed to decompose in order to produce 65.0 L of water at STP in stoichiometry?

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  1. 19 May, 05:08
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    Aluminium Hydroxide on decomposition produces Al₂O₃ and Water vapors.

    2 Al (OH) ₃ → Al₂O₃ + 3 H₂O

    According to equation at STP,

    67.2 L (3 moles) of H₂O is produced by = 78 g of Al (OH) ₃

    So,

    65.0 L of H₂O will be produced by = X g of Al (OH) ₃

    Solving for X,

    X = (65.0 L * 78 g) : 67.2 L

    X = 75.44 g of Al (OH) ₂

    Result:

    75.44 g of Al (OH) ₂ is needed to decompose in order to produce 65.0 L of water at STP in stoichiometry
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