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16 April, 20:27

what grade is learning What amount of thermal energy (heat) in joules required to raise the temperature of 25 grams of water from 0 degrees C to 100 degrees C?

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  1. 16 April, 22:13
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    10425 J are required

    Explanation:

    assuming that the water is entirely at liquid state at the beginning, the amount required is

    Q = m*c * (T final - T initial)

    where

    m = mass of water = 25 g

    T final = final temperature of water = 100°C

    T initial = initial temperature of water = 0°C

    c = specific heat capacities of water = 1 cal / g°C = 4.186 J/g°C (we assume that is constant during the entire temperature range)

    Q = heat required

    therefore

    Q = m*c * (T final - T initial) = 25 g * 4.186 J/g°C * (100°C - 0°C) = 10425 J

    thus 10425 J are required
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