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7 June, 19:32

A metal stand specifies a maximum load of 450 lb. Will it support an aquarium that weighs 59.5 lb and is filled with 37.9 L of seawater (d = 1.03 g/mL) ?

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  1. 7 June, 19:51
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    First solve the mass of 37.9 L seawater

    M = 37.9 L (1000 ml / 1L) (1.03 g / ml)

    M = 39037 g

    Then convert it to lb

    M = 39037 g (1 lb / 453.592 g)

    M = 86.06 lb

    Total weight = 86.06 lb + 59.5 lb = 145.56 lb so it can support the aquarium
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