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18 May, 06:52

Combustion analysis of a 13.42-g sample of estriol (which contains only carbon, hydrogen, and oxygen) produced 36.86 g CO2 and 10.06 g H2O. The molar mass of estriol is 288.38 g/mol. Find the molecular formula for estriol. Express your answer as a chemical formula.

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  1. 18 May, 06:55
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    C18H24O3

    Explanation:

    Step 1:

    Data obtained from the question. This include the following:

    Mass of estriol = 13.42g

    Mass of CO2 = 36.86g

    Mass of H2O = 10.06g

    Molar mass of estriol = 288.38g/mol

    Step 2:

    Determination of the mass of Carbon (C), Hydrogen (H) and Oxygen (O) present in the compound. This is illustrated below:

    For Carbon, C:

    Molar mass of CO2 = 12 + (2x16) = 44g/mol

    Mass of C in CO2 = 12/44 x 36.86 = 10.05g

    For Hydrogen, H:

    Molar Mass of H2O = (2x1) + 16 = 18g/mol

    Mass of H in H2O = 2/18 x 10.06 = 1.12g

    For Oxygen, O:

    Mass of O = 13.42 - (10.05 + 1.12) = 2.25g

    Step 3:

    Determination of the empirical formula for estriol. This is illustrated below:

    C = 10.05g

    H = 1.12g

    O = 2.25g

    Divide by their molar mass

    C = 10.05/12 = 0.8375

    H = 1.12/1 = 1.12

    O = 2.25/16 = 0.1406

    Divide by the smallest i. e 0.1406

    C = 0.8375/0.1406 = 6

    H = 1.12/0.1406 = 8

    O = 0.1406/0.1406 = 1

    Therefore, the empirical formula for estriol is C6H8O

    Step 4:

    Determination of the molecular formula for estriol. This is illustrated below:

    Molecular formula is simply a multiple of the empirical formula i. e

    Molecular formula = > [C6H8O]n

    [C6H8O]n = 288.38g/mol

    [ (12x6) + (8x1) + 16]n = 288.38

    [72 + 8 + 16]n = 288.38

    96n = 288.38

    Divide both side by 96

    n = 288.38/96 = 3

    Molecular formula = > [C6H8O]n

    => [C6H8O]n

    => [C6H8O]3

    => C18H24O3

    Therefore, the molecular formula for estriol is C18H24O3
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