18 April, 11:58
How many grams of cacl2 are present in 25ml of a 0.500m solution?
18 April, 13:25
The grams of cacl2 are presented in 25 ml of a 0.500 M solution is calculated as follows
find the number of moles
moles = molarity x volume/1000
= 0.500 x25 / 1000 = 0.0125 moles
mass = moles x molar mass of cacl2
= 0.0125 mol x 111.1 g/mol = 1.389 grams
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