The molar heat of fusion for water is 6.01 kJ/mol. How much energy must be added to a 75.0-g block of ice at 0°C to change it to 75.0 g of liquid water at 0°C?

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Cameron Bryan

Chemistry

Today, 20:21

The molar heat of fusion for water is 6.01 kJ/mol. How much energy must be added to a 75.0-g block of ice at 0°C to change it to 75.0 g of liquid water at 0°C?

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Marlie · Answer 1

Answer is: 25,06 kJ of energy must be added to a 75 g block of ice.

ΔHfusion (H₂O) = 6,01 kJ/mol.

T (H₂O) = 0°C.

m (H₂O) = 75 g.

n (H₂O) = m (H₂O) : M (H₂O).

n (H₂O) = 75 g : 18 g/mol.

n (H₂O) = 4,17 mol.

Q = ΔHfusion (H₂O) · n (H₂O)

Q = 6,01 kJ/mol · 4,17 mol

Q = 25,06 kJ.