Be sure to answer all parts. List the following bonds in order of decreasing ionic character: cesium to fluorine, chlorine to chlorine, bromine to chlorine, silicon to carbon. (Enter the two elements of the bond into the appropriate box: CsF, ClCl, BrCl, SiC)

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Obrien

Chemistry

14 July, 10:57

Be sure to answer all parts. List the following bonds in order of decreasing ionic character: cesium to fluorine, chlorine to chlorine, bromine to chlorine, silicon to carbon. (Enter the two elements of the bond into the appropriate box: CsF, ClCl, BrCl, SiC)

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Eve Snow · Answer 1

Trend in ionic character of bonds: Cs-F > Si-C > Br-Cl > Cl-Cl

(most) (least)

Explanation:

We know that, percentage ionic character of a bond is proportional to electronegativity difference between two constituting atoms.

Atom Electronegativity

Cs 0.7

F 4.0

Cl 3.0

Br 2.8

Si 1.8

C 2.5

Bond Electronegativity difference

Cs-F 3.3

Cl-Cl 0.0

Br-Cl 0.2

Si-C 0.7

So trend in ionic character of bonds:

Cs-F > Si-C > Br-Cl > Cl-Cl

(most) (least)