Bases on Graham's law of diffusion, how does the speed of diffusion of neon (M=20.2) compare to the Krpton (M=83.8)

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Camden Cisneros

Chemistry

14 July, 19:50

Bases on Graham's law of diffusion, how does the speed of diffusion of neon (M=20.2) compare to the Krpton (M=83.8)

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Bozley · Answer 1

2.037.

Explanation:

Thomas Graham found that, at a constant temperature and pressure the rates of effusion of various gases are inversely proportional to the square root of their masses.

∨ ∝ 1/√M.

Where, ∨ is the rate of diffusion.

M is the molar mass of the gas.

For Ne and Kr:

(∨) Ne / (∨) Kr = √ (M of Kr/M of Ne) = √ (83.8 / 20.2) = 2.037.