A compound with a molar mass of 100.0 g/lol has an elemental composition of 24.0% C, 3.0% H, 16.0% O and 57.0%F. What is the molecular formula of the compound?

If I made no mistake in calculation, the given answer must be correct ... (tried my best)

elements : carbon hydrogen oxygen Fluorine

composition [C] 24 3 16 57

M r 12 1 16 19

(divide C by Mr) 2 3 1 3

(Divide by smallest value) 2 3 1 3

(smallest value = 1 ... so all value remained constant)

Empirical formula : C2H3OF3

if molar mas = 100 g per mole, then

first step calculate Mr. of empirical formula: [ = 100]

Them molecular formula = empirical formula