How many atoms of phosphorus are represented in 2ca3 (po4) 2?

Two atoms of phosphorus are present in the compound.

2Ca₃ (PO₄) ₂ contains 2 moles of phosphorus per mole, and there are 2 moles present. Therefore, there are a total of 4 moles of phosphorus present. Each mole contains 6.02 x 10²³ atoms. The atoms of phosphorus are:

6.02 x 10²³ x 4

= 2.408 x 10²⁴ atoms